10=-6(x-3)+2x

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Solution for 10=-6(x-3)+2x equation: 



10=-6(x-3)+2x

We move all terms to the left:

10-(-6(x-3)+2x)=0



We calculate terms in parentheses: -(-6(x-3)+2x), so:

-6(x-3)+2x

We add all the numbers together, and all the variables

2x-6(x-3)

We multiply parentheses

2x-6x+18

We add all the numbers together, and all the variables

-4x+18

Back to the equation:

-(-4x+18)



We get rid of parentheses

4x-18+10=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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