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-2x(6-3x)=-12+6x
We move all terms to the left:
-2x(6-3x)-(-12+6x)=0
We add all the numbers together, and all the variables
-2x(-3x+6)-(6x-12)=0
We multiply parentheses
6x^2-12x-(6x-12)=0
We get rid of parentheses
6x^2-12x-6x+12=0
We add all the numbers together, and all the variables
6x^2-18x+12=0
a = 6; b = -18; c = +12;
Δ = b2-4ac
Δ = -182-4·6·12
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6}{2*6}=\frac{12}{12} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6}{2*6}=\frac{24}{12} =2 $
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