7(y-1)+2(y+2)=2(y-3)-5

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Solution for 7(y-1)+2(y+2)=2(y-3)-5 equation: 



7(y-1)+2(y+2)=2(y-3)-5

We move all terms to the left:

7(y-1)+2(y+2)-(2(y-3)-5)=0

We multiply parentheses

7y+2y-(2(y-3)-5)-7+4=0



We calculate terms in parentheses: -(2(y-3)-5), so:

2(y-3)-5

We multiply parentheses

2y-6-5

We add all the numbers together, and all the variables

2y-11

Back to the equation:

-(2y-11)



We add all the numbers together, and all the variables

9y-(2y-11)-3=0

We get rid of parentheses

9y-2y+11-3=0

We add all the numbers together, and all the variables

7y+8=0

We move all terms containing y to the left, all other terms to the right

7y=-8

y=-8/7

y=-1+1/7

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