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5x(x-1)=35
We move all terms to the left:
5x(x-1)-(35)=0
We multiply parentheses
5x^2-5x-35=0
a = 5; b = -5; c = -35;
Δ = b2-4ac
Δ = -52-4·5·(-35)
Δ = 725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{725}=\sqrt{25*29}=\sqrt{25}*\sqrt{29}=5\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{29}}{2*5}=\frac{5-5\sqrt{29}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{29}}{2*5}=\frac{5+5\sqrt{29}}{10} $
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