10800=3x(2x*1)12

Solution for 10800=3x(2x*1)12 equation:

10800=3x(2x*1)12

We move all terms to the left:

10800-(3x(2x*1)12)=0

We add all the numbers together, and all the variables

-(3x(+2x*1)12)+10800=0


We calculate terms in parentheses: -(3x(+2x*1)12), so:

3x(+2x*1)12

We multiply parentheses

72x^2

Back to the equation:

-(72x^2)


a = -72; b = 0; c = +10800;
Δ = b2-4ac
Δ = 02-4·(-72)·10800
Δ = 3110400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3110400}=\sqrt{518400*6}=\sqrt{518400}*\sqrt{6}=720\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-720\sqrt{6}}{2*-72}=\frac{0-720\sqrt{6}}{-144}
=-\frac{720\sqrt{6}}{-144}
=-\frac{5\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+720\sqrt{6}}{2*-72}=\frac{0+720\sqrt{6}}{-144}
=\frac{720\sqrt{6}}{-144}
=\frac{5\sqrt{6}}{-1}
$