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10x+9-x-11=-2(2x+4)-3(2x-2)
We move all terms to the left:
10x+9-x-11-(-2(2x+4)-3(2x-2))=0
We add all the numbers together, and all the variables
9x-(-2(2x+4)-3(2x-2))-2=0
We calculate terms in parentheses: -(-2(2x+4)-3(2x-2)), so:We get rid of parentheses
-2(2x+4)-3(2x-2)
We multiply parentheses
-4x-6x-8+6
We add all the numbers together, and all the variables
-10x-2
Back to the equation:
-(-10x-2)
9x+10x+2-2=0
We add all the numbers together, and all the variables
19x=0
x=0/19
x=0
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