105(n+1)+4(n-1)=117(5+n)-(25-3n)

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Solution for 105(n+1)+4(n-1)=117(5+n)-(25-3n) equation: 



105(n+1)+4(n-1)=117(5+n)-(25-3n)

We move all terms to the left:

105(n+1)+4(n-1)-(117(5+n)-(25-3n))=0

We add all the numbers together, and all the variables

105(n+1)+4(n-1)-(117(n+5)-(-3n+25))=0

We multiply parentheses

105n+4n-(117(n+5)-(-3n+25))+105-4=0



We calculate terms in parentheses: -(117(n+5)-(-3n+25)), so:

117(n+5)-(-3n+25)

We multiply parentheses

117n-(-3n+25)+585

We get rid of parentheses

117n+3n-25+585

We add all the numbers together, and all the variables

120n+560

Back to the equation:

-(120n+560)



We add all the numbers together, and all the variables

109n-(120n+560)+101=0

We get rid of parentheses

109n-120n-560+101=0

We add all the numbers together, and all the variables

-11n-459=0

We move all terms containing n to the left, all other terms to the right

-11n=459

n=459/-11

n=-41+8/11

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