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6(x-1)=3(2-x)+3x
We move all terms to the left:
6(x-1)-(3(2-x)+3x)=0
We add all the numbers together, and all the variables
6(x-1)-(3(-1x+2)+3x)=0
We multiply parentheses
6x-(3(-1x+2)+3x)-6=0
We calculate terms in parentheses: -(3(-1x+2)+3x), so:We add all the numbers together, and all the variables
3(-1x+2)+3x
We add all the numbers together, and all the variables
3x+3(-1x+2)
We multiply parentheses
3x-3x+6
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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