103=-4b-5(3b+6)

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Solution for 103=-4b-5(3b+6) equation: 



103=-4b-5(3b+6)

We move all terms to the left:

103-(-4b-5(3b+6))=0



We calculate terms in parentheses: -(-4b-5(3b+6)), so:

-4b-5(3b+6)

We multiply parentheses

-4b-15b-30

We add all the numbers together, and all the variables

-19b-30

Back to the equation:

-(-19b-30)



We get rid of parentheses

19b+30+103=0

We add all the numbers together, and all the variables

19b+133=0

We move all terms containing b to the left, all other terms to the right

19b=-133

b=-133/19

b=-7

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