5/4x+7=13+x

Solution for 5/4x+7=13+x equation:

5/4x+7=13+x

We move all terms to the left:

5/4x+7-(13+x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

5/4x-(x+13)+7=0

We get rid of parentheses

5/4x-x-13+7=0

We multiply all the terms by the denominator


-x*4x-13*4x+7*4x+5=0

Wy multiply elements

-4x^2-52x+28x+5=0

We add all the numbers together, and all the variables

-4x^2-24x+5=0

a = -4; b = -24; c = +5;
Δ = b2-4ac
Δ = -242-4·(-4)·5
Δ = 656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{656}=\sqrt{16*41}=\sqrt{16}*\sqrt{41}=4\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{41}}{2*-4}=\frac{24-4\sqrt{41}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{41}}{2*-4}=\frac{24+4\sqrt{41}}{-8}
$