3(x-1)-8=4(1+x)

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Solution for 3(x-1)-8=4(1+x) equation: 



3(x-1)-8=4(1+x)

We move all terms to the left:

3(x-1)-8-(4(1+x))=0

We add all the numbers together, and all the variables

3(x-1)-(4(x+1))-8=0

We multiply parentheses

3x-(4(x+1))-3-8=0



We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

3x-(4x+4)-11=0

We get rid of parentheses

3x-4x-4-11=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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