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1024=h2
We move all terms to the left:
1024-(h2)=0
We add all the numbers together, and all the variables
-1h^2+1024=0
a = -1; b = 0; c = +1024;
Δ = b2-4ac
Δ = 02-4·(-1)·1024
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-1}=\frac{-64}{-2} =+32 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-1}=\frac{64}{-2} =-32 $
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