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5(x+3)=(2x-29)
We move all terms to the left:
5(x+3)-((2x-29))=0
We multiply parentheses
5x-((2x-29))+15=0
We calculate terms in parentheses: -((2x-29)), so:We get rid of parentheses
(2x-29)
We get rid of parentheses
2x-29
Back to the equation:
-(2x-29)
5x-2x+29+15=0
We add all the numbers together, and all the variables
3x+44=0
We move all terms containing x to the left, all other terms to the right
3x=-44
x=-44/3
x=-14+2/3
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