2x2+5x=207

Solution for 2x2+5x=207 equation:

2x^2+5x=207

We move all terms to the left:

2x^2+5x-(207)=0

a = 2; b = 5; c = -207;
Δ = b2-4ac
Δ = 52-4·2·(-207)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-41}{2*2}=\frac{-46}{4}
=-11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+41}{2*2}=\frac{36}{4}
=9
$