1000(6x-10)=40(315+100x

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Solution for 1000(6x-10)=40(315+100x equation: 



1000(6x-10)=40(315+100x

We move all terms to the left:

1000(6x-10)-(40(315+100x)=0

We add all the numbers together, and all the variables

1000(6x-10)-(40(100x+315)=0

We multiply parentheses

6000x-(40(100x+315)-10000=0

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