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(2x+45)x=180
We move all terms to the left:
(2x+45)x-(180)=0
We multiply parentheses
2x^2+45x-180=0
a = 2; b = 45; c = -180;
Δ = b2-4ac
Δ = 452-4·2·(-180)
Δ = 3465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3465}=\sqrt{9*385}=\sqrt{9}*\sqrt{385}=3\sqrt{385}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3\sqrt{385}}{2*2}=\frac{-45-3\sqrt{385}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3\sqrt{385}}{2*2}=\frac{-45+3\sqrt{385}}{4} $
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