2a(5a+13)=0

Solution for 2a(5a+13)=0 equation:

2a(5a+13)=0

We multiply parentheses

10a^2+26a=0

a = 10; b = 26; c = 0;
Δ = b2-4ac
Δ = 262-4·10·0
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-26}{2*10}=\frac{-52}{20}
=-2+3/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+26}{2*10}=\frac{0}{20}
=0
$