1000(1+r)2=600(1+r)+800

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Solution for 1000(1+r)2=600(1+r)+800 equation: 



1000(1+r)2=600(1+r)+800

We move all terms to the left:

1000(1+r)2-(600(1+r)+800)=0

We add all the numbers together, and all the variables

1000(r+1)2-(600(r+1)+800)=0

We multiply parentheses

2000r-(600(r+1)+800)+2000=0



We calculate terms in parentheses: -(600(r+1)+800), so:

600(r+1)+800

We multiply parentheses

600r+600+800

We add all the numbers together, and all the variables

600r+1400

Back to the equation:

-(600r+1400)



We get rid of parentheses

2000r-600r-1400+2000=0

We add all the numbers together, and all the variables

1400r+600=0

We move all terms containing r to the left, all other terms to the right

1400r=-600

r=-600/1400

r=-3/7

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