(X+3)/3=1-(x+4)/7

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Solution for (X+3)/3=1-(x+4)/7 equation: 



(X+3)/3=1-(X+4)/7

We move all terms to the left:

(X+3)/3-(1-(X+4)/7)=0

We calculate fractions


X/()+(-(1-(X+4)*3)/()=0



We calculate terms in parentheses: +(-(1-(X+4)*3)/(), so:

-(1-(X+4)*3)/(

We multiply all the terms by the denominator


-(1-(X+4)*3)



We calculate terms in parentheses: -(1-(X+4)*3), so:

1-(X+4)*3

determiningTheFunctionDomain
-(X+4)*3+1

We multiply parentheses

-3X-12+1

We add all the numbers together, and all the variables

-3X-11

Back to the equation:

-(-3X-11)



We get rid of parentheses

3X+11

Back to the equation:

+(3X+11)



We get rid of parentheses

X/()+3X+11=0

We multiply all the terms by the denominator


X+3X*()+11*()=0

We add all the numbers together, and all the variables

X+3X*()=0

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