6(4z-1)-2(z+6)=9(z+1)

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Solution for 6(4z-1)-2(z+6)=9(z+1) equation: 



6(4z-1)-2(z+6)=9(z+1)

We move all terms to the left:

6(4z-1)-2(z+6)-(9(z+1))=0

We multiply parentheses

24z-2z-(9(z+1))-6-12=0



We calculate terms in parentheses: -(9(z+1)), so:

9(z+1)

We multiply parentheses

9z+9

Back to the equation:

-(9z+9)



We add all the numbers together, and all the variables

22z-(9z+9)-18=0

We get rid of parentheses

22z-9z-9-18=0

We add all the numbers together, and all the variables

13z-27=0

We move all terms containing z to the left, all other terms to the right

13z=27

z=27/13

z=2+1/13

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