100+(6x-8)=4(3x-4)+52

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Solution for 100+(6x-8)=4(3x-4)+52 equation: 



100+(6x-8)=4(3x-4)+52

We move all terms to the left:

100+(6x-8)-(4(3x-4)+52)=0

We get rid of parentheses

6x-(4(3x-4)+52)-8+100=0



We calculate terms in parentheses: -(4(3x-4)+52), so:

4(3x-4)+52

We multiply parentheses

12x-16+52

We add all the numbers together, and all the variables

12x+36

Back to the equation:

-(12x+36)



We add all the numbers together, and all the variables

6x-(12x+36)+92=0

We get rid of parentheses

6x-12x-36+92=0

We add all the numbers together, and all the variables

-6x+56=0

We move all terms containing x to the left, all other terms to the right

-6x=-56

x=-56/-6

x=9+1/3

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