-7(4-2v)=36+6v

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Solution for -7(4-2v)=36+6v equation: 



-7(4-2v)=36+6v

We move all terms to the left:

-7(4-2v)-(36+6v)=0

We add all the numbers together, and all the variables

-7(-2v+4)-(6v+36)=0

We multiply parentheses

14v-(6v+36)-28=0

We get rid of parentheses

14v-6v-36-28=0

We add all the numbers together, and all the variables

8v-64=0

We move all terms containing v to the left, all other terms to the right

8v=64

v=64/8

v=8

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