x=3-(x+3)(x+3)

Solution for x=3-(x+3)(x+3) equation:

x=3-(x+3)(x+3)

We move all terms to the left:

x-(3-(x+3)(x+3))=0

We multiply parentheses ..

-(3-(+x^2+3x+3x+9))+x=0


We calculate terms in parentheses: -(3-(+x^2+3x+3x+9)), so:

3-(+x^2+3x+3x+9)

determiningTheFunctionDomain
-(+x^2+3x+3x+9)+3

We get rid of parentheses

-x^2-3x-3x-9+3

We add all the numbers together, and all the variables

-1x^2-6x-6

Back to the equation:

-(-1x^2-6x-6)


We get rid of parentheses

1x^2+6x+x+6=0

We add all the numbers together, and all the variables

x^2+7x+6=0

a = 1; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·1·6
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-5}{2*1}=\frac{-12}{2}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+5}{2*1}=\frac{-2}{2}
=-1
$