100(z-0.2)=10(5z+0.8)

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Solution for 100(z-0.2)=10(5z+0.8) equation: 



100(z-0.2)=10(5z+0.8)

We move all terms to the left:

100(z-0.2)-(10(5z+0.8))=0

We multiply parentheses

100z-(10(5z+0.8))-20=0



We calculate terms in parentheses: -(10(5z+0.8)), so:

10(5z+0.8)

We multiply parentheses

50z+8

Back to the equation:

-(50z+8)



We get rid of parentheses

100z-50z-8-20=0

We add all the numbers together, and all the variables

50z-28=0

We move all terms containing z to the left, all other terms to the right

50z=28

z=28/50

z=14/25

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