2-(x+5)=3+(x+3)

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Solution for 2-(x+5)=3+(x+3) equation: 



2-(x+5)=3+(x+3)

We move all terms to the left:

2-(x+5)-(3+(x+3))=0

We get rid of parentheses

-x-(3+(x+3))-5+2=0



We calculate terms in parentheses: -(3+(x+3)), so:

3+(x+3)

determiningTheFunctionDomain
(x+3)+3

We get rid of parentheses

x+3+3

We add all the numbers together, and all the variables

x+6

Back to the equation:

-(x+6)



We add all the numbers together, and all the variables

-1x-(x+6)-3=0

We get rid of parentheses

-1x-x-6-3=0

We add all the numbers together, and all the variables

-2x-9=0

We move all terms containing x to the left, all other terms to the right

-2x=9

x=9/-2

x=-4+1/2

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