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2(6x^2-3)=11x^2
We move all terms to the left:
2(6x^2-3)-(11x^2)=0
determiningTheFunctionDomain -11x^2+2(6x^2-3)=0
We multiply parentheses
-11x^2+12x^2-6=0
We add all the numbers together, and all the variables
x^2-6=0
a = 1; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·1·(-6)
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{6}}{2*1}=\frac{0-2\sqrt{6}}{2} =-\frac{2\sqrt{6}}{2} =-\sqrt{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{6}}{2*1}=\frac{0+2\sqrt{6}}{2} =\frac{2\sqrt{6}}{2} =\sqrt{6} $
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