10-9(5-4a)=5(7a-5)

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Solution for 10-9(5-4a)=5(7a-5) equation: 



10-9(5-4a)=5(7a-5)

We move all terms to the left:

10-9(5-4a)-(5(7a-5))=0

We add all the numbers together, and all the variables

-9(-4a+5)-(5(7a-5))+10=0

We multiply parentheses

36a-(5(7a-5))-45+10=0



We calculate terms in parentheses: -(5(7a-5)), so:

5(7a-5)

We multiply parentheses

35a-25

Back to the equation:

-(35a-25)



We add all the numbers together, and all the variables

36a-(35a-25)-35=0

We get rid of parentheses

36a-35a+25-35=0

We add all the numbers together, and all the variables

a-10=0

We move all terms containing a to the left, all other terms to the right

a=10

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