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2/x+6/5x=3
We move all terms to the left:
2/x+6/5x-(3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
10x/5x^2+6x/5x^2-3=0
We multiply all the terms by the denominator
10x+6x-3*5x^2=0
We add all the numbers together, and all the variables
16x-3*5x^2=0
Wy multiply elements
-15x^2+16x=0
a = -15; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-15)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-15}=\frac{-32}{-30} =1+1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-15}=\frac{0}{-30} =0 $
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