10-4x=5(3-2x)+7

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Solution for 10-4x=5(3-2x)+7 equation: 



10-4x=5(3-2x)+7

We move all terms to the left:

10-4x-(5(3-2x)+7)=0

We add all the numbers together, and all the variables

-4x-(5(-2x+3)+7)+10=0



We calculate terms in parentheses: -(5(-2x+3)+7), so:

5(-2x+3)+7

We multiply parentheses

-10x+15+7

We add all the numbers together, and all the variables

-10x+22

Back to the equation:

-(-10x+22)



We get rid of parentheses

-4x+10x-22+10=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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