3t-2(7-2)=5(2t+4)

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Solution for 3t-2(7-2)=5(2t+4) equation: 



3t-2(7-2)=5(2t+4)

We move all terms to the left:

3t-2(7-2)-(5(2t+4))=0

We add all the numbers together, and all the variables

3t-(5(2t+4))-25=0



We calculate terms in parentheses: -(5(2t+4)), so:

5(2t+4)

We multiply parentheses

10t+20

Back to the equation:

-(10t+20)



We get rid of parentheses

3t-10t-20-25=0

We add all the numbers together, and all the variables

-7t-45=0

We move all terms containing t to the left, all other terms to the right

-7t=45

t=45/-7

t=-6+3/7

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