3t-2(7-t)=5(2t+4)

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Solution for 3t-2(7-t)=5(2t+4) equation: 



3t-2(7-t)=5(2t+4)

We move all terms to the left:

3t-2(7-t)-(5(2t+4))=0

We add all the numbers together, and all the variables

3t-2(-1t+7)-(5(2t+4))=0

We multiply parentheses

3t+2t-(5(2t+4))-14=0



We calculate terms in parentheses: -(5(2t+4)), so:

5(2t+4)

We multiply parentheses

10t+20

Back to the equation:

-(10t+20)



We add all the numbers together, and all the variables

5t-(10t+20)-14=0

We get rid of parentheses

5t-10t-20-14=0

We add all the numbers together, and all the variables

-5t-34=0

We move all terms containing t to the left, all other terms to the right

-5t=34

t=34/-5

t=-6+4/5

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