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10-3(x+5)=13-6(x+2)
We move all terms to the left:
10-3(x+5)-(13-6(x+2))=0
We multiply parentheses
-3x-(13-6(x+2))-15+10=0
We calculate terms in parentheses: -(13-6(x+2)), so:We add all the numbers together, and all the variables
13-6(x+2)
determiningTheFunctionDomain -6(x+2)+13
We multiply parentheses
-6x-12+13
We add all the numbers together, and all the variables
-6x+1
Back to the equation:
-(-6x+1)
-3x-(-6x+1)-5=0
We get rid of parentheses
-3x+6x-1-5=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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