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2x+3/x=12x
We move all terms to the left:
2x+3/x-(12x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
-10x+3/x=0
We multiply all the terms by the denominator
-10x*x+3=0
Wy multiply elements
-10x^2+3=0
a = -10; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-10)·3
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*-10}=\frac{0-2\sqrt{30}}{-20} =-\frac{2\sqrt{30}}{-20} =-\frac{\sqrt{30}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*-10}=\frac{0+2\sqrt{30}}{-20} =\frac{2\sqrt{30}}{-20} =\frac{\sqrt{30}}{-10} $
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