10-3(2b+4)=4b-2b(5-b)

Solution for 10-3(2b+4)=4b-2b(5-b) equation:

10-3(2b+4)=4b-2b(5-b)

We move all terms to the left:

10-3(2b+4)-(4b-2b(5-b))=0

We add all the numbers together, and all the variables

-3(2b+4)-(4b-2b(-1b+5))+10=0

We multiply parentheses

-6b-(4b-2b(-1b+5))-12+10=0


We calculate terms in parentheses: -(4b-2b(-1b+5)), so:

4b-2b(-1b+5)

We multiply parentheses

2b^2+4b-10b

We add all the numbers together, and all the variables

2b^2-6b

Back to the equation:

-(2b^2-6b)


We add all the numbers together, and all the variables

-6b-(2b^2-6b)-2=0

We get rid of parentheses

-2b^2-6b+6b-2=0

We add all the numbers together, and all the variables

-2b^2-2=0

a = -2; b = 0; c = -2;
Δ = b2-4ac
Δ = 02-4·(-2)·(-2)
Δ = -16
Delta is less than zero, so there is no solution for the equation