10(y-3)+4y=58

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Solution for 10(y-3)+4y=58 equation: 



10(y-3)+4y=58

We move all terms to the left:

10(y-3)+4y-(58)=0

We add all the numbers together, and all the variables

4y+10(y-3)-58=0

We multiply parentheses

4y+10y-30-58=0

We add all the numbers together, and all the variables

14y-88=0

We move all terms containing y to the left, all other terms to the right

14y=88

y=88/14

y=6+2/7

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