D=5t2

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Solution for D=5t2 equation: 



=5D^2

We move all terms to the left:

-(5D^2)=0

a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$D=\frac{-b}{2a}=\frac{0}{-10}=0$

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