10(c-3)+3=2+c-29

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Solution for 10(c-3)+3=2+c-29 equation: 



10(c-3)+3=2+c-29

We move all terms to the left:

10(c-3)+3-(2+c-29)=0

We add all the numbers together, and all the variables

10(c-3)-(c-27)+3=0

We multiply parentheses

10c-(c-27)-30+3=0

We get rid of parentheses

10c-c+27-30+3=0

We add all the numbers together, and all the variables

9c=0

c=0/9

c=0

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