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x(9x+1)=88
We move all terms to the left:
x(9x+1)-(88)=0
We multiply parentheses
9x^2+x-88=0
a = 9; b = 1; c = -88;
Δ = b2-4ac
Δ = 12-4·9·(-88)
Δ = 3169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{3169}}{2*9}=\frac{-1-\sqrt{3169}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{3169}}{2*9}=\frac{-1+\sqrt{3169}}{18} $
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