2/3(c-18)=7c=

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Solution for 2/3(c-18)=7c= equation: 



2/3(c-18)=7c=

We move all terms to the left:

2/3(c-18)-(7c)=0



Domain of the equation: 3(c-18)!=0

c∈R



We add all the numbers together, and all the variables

-7c+2/3(c-18)=0

We multiply all the terms by the denominator


-7c*3(c-18)+2=0

Wy multiply elements

-21c^2(c+2=0

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