10(8+4/5b)=10(9/10b)

Solution for 10(8+4/5b)=10(9/10b) equation:

10(8+4/5b)=10(9/10b)

We move all terms to the left:

10(8+4/5b)-(10(9/10b))=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



Domain of the equation: 10b))!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

10(4/5b+8)-(10(+9/10b))=0

We multiply parentheses

40b-(10(+9/10b))+80=0

We multiply all the terms by the denominator


40b*10b))-(10(+80*10b))+9=0

Wy multiply elements

400b^2+800b=0

a = 400; b = 800; c = 0;
Δ = b2-4ac
Δ = 8002-4·400·0
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(800)-800}{2*400}=\frac{-1600}{800}
=-2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(800)+800}{2*400}=\frac{0}{800}
=0
$