z(3-z)-7=42

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Solution for z(3-z)-7=42 equation: 



z(3-z)-7=42

We move all terms to the left:

z(3-z)-7-(42)=0

We add all the numbers together, and all the variables

z(-1z+3)-7-42=0

We add all the numbers together, and all the variables

z(-1z+3)-49=0

We multiply parentheses

-1z^2+3z-49=0

a = -1; b = 3; c = -49;
Δ = b2-4ac
Δ = 32-4·(-1)·(-49)
Δ = -187
Delta is less than zero, so there is no solution for the equation

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