10(7/10x-2)=10(2/5x+1)

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Solution for 10(7/10x-2)=10(2/5x+1) equation: 



10(7/10x-2)=10(2/5x+1)

We move all terms to the left:

10(7/10x-2)-(10(2/5x+1))=0



Domain of the equation: 10x-2)!=0

x∈R





Domain of the equation: 5x+1))!=0

x∈R



We multiply parentheses

70x-(10(2/5x+1))-20=0

We multiply all the terms by the denominator


70x*5x-20*5x+1))-(10(2+1))=0

We add all the numbers together, and all the variables

70x*5x-20*5x+1))-(103)=0

We add all the numbers together, and all the variables

70x*5x-20*5x=0

Wy multiply elements

350x^2-100x=0

a = 350; b = -100; c = 0;
Δ = b2-4ac
Δ = -1002-4·350·0
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-100}{2*350}=\frac{0}{700}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+100}{2*350}=\frac{200}{700}
=2/7
$

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