9(x-4)=-6+3(x+12)

Solution for 9(x-4)=-6+3(x+12) equation:

9(x-4)=-6+3(x+12)

We move all terms to the left:

9(x-4)-(-6+3(x+12))=0

We multiply parentheses

9x-(-6+3(x+12))-36=0


We calculate terms in parentheses: -(-6+3(x+12)), so:

-6+3(x+12)

determiningTheFunctionDomain
3(x+12)-6

We multiply parentheses

3x+36-6

We add all the numbers together, and all the variables

3x+30

Back to the equation:

-(3x+30)


We get rid of parentheses

9x-3x-30-36=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11