2(y-4)-3y=-4(y+8)

Solution for 2(y-4)-3y=-4(y+8) equation:

2(y-4)-3y=-4(y+8)

We move all terms to the left:

2(y-4)-3y-(-4(y+8))=0

We add all the numbers together, and all the variables

-3y+2(y-4)-(-4(y+8))=0

We multiply parentheses

-3y+2y-(-4(y+8))-8=0


We calculate terms in parentheses: -(-4(y+8)), so:

-4(y+8)

We multiply parentheses

-4y-32

Back to the equation:

-(-4y-32)


We add all the numbers together, and all the variables

-1y-(-4y-32)-8=0

We get rid of parentheses

-1y+4y+32-8=0

We add all the numbers together, and all the variables

3y+24=0

We move all terms containing y to the left, all other terms to the right

3y=-24

y=-24/3

y=-8