10(1-3)=-8(6v+1)

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Solution for 10(1-3)=-8(6v+1) equation: 



10(1-3)=-8(6v+1)

We move all terms to the left:

10(1-3)-(-8(6v+1))=0

We add all the numbers together, and all the variables

-(-8(6v+1))+10(-2)=0

We add all the numbers together, and all the variables

-(-8(6v+1))-20=0



We calculate terms in parentheses: -(-8(6v+1)), so:

-8(6v+1)

We multiply parentheses

-48v-8

Back to the equation:

-(-48v-8)



We get rid of parentheses

48v+8-20=0

We add all the numbers together, and all the variables

48v-12=0

We move all terms containing v to the left, all other terms to the right

48v=12

v=12/48

v=1/4

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