10(1+2b)=-10-10b-10

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Solution for 10(1+2b)=-10-10b-10 equation: 



10(1+2b)=-10-10b-10

We move all terms to the left:

10(1+2b)-(-10-10b-10)=0

We add all the numbers together, and all the variables

10(2b+1)-(-10b-20)=0

We multiply parentheses

20b-(-10b-20)+10=0

We get rid of parentheses

20b+10b+20+10=0

We add all the numbers together, and all the variables

30b+30=0

We move all terms containing b to the left, all other terms to the right

30b=-30

b=-30/30

b=-1

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