1/212(6x-4)=1/3(12x-15)

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Solution for 1/212(6x-4)=1/3(12x-15) equation: 



1/212(6x-4)=1/3(12x-15)

We move all terms to the left:

1/212(6x-4)-(1/3(12x-15))=0



Domain of the equation: 212(6x-4)!=0

x∈R





Domain of the equation: 3(12x-15))!=0

x∈R



We calculate fractions


(3x1/(212(6x-4)*3(12x-15)))+(-212x6/(212(6x-4)*3(12x-15)))=0



We calculate terms in parentheses: +(3x1/(212(6x-4)*3(12x-15))), so:

3x1/(212(6x-4)*3(12x-15))

We multiply all the terms by the denominator


3x1

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-212x6/(212(6x-4)*3(12x-15))), so:

-212x6/(212(6x-4)*3(12x-15))

We multiply all the terms by the denominator


-212x6

We add all the numbers together, and all the variables

-212x^6

We do not support expression: x^6

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