2(2x+3)-8(x-5)=2

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Solution for 2(2x+3)-8(x-5)=2 equation: 



2(2x+3)-8(x-5)=2

We move all terms to the left:

2(2x+3)-8(x-5)-(2)=0

We multiply parentheses

4x-8x+6+40-2=0

We add all the numbers together, and all the variables

-4x+44=0

We move all terms containing x to the left, all other terms to the right

-4x=-44

x=-44/-4

x=+11

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