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10(-4x-7)x=2
We move all terms to the left:
10(-4x-7)x-(2)=0
We multiply parentheses
-40x^2-70x-2=0
a = -40; b = -70; c = -2;
Δ = b2-4ac
Δ = -702-4·(-40)·(-2)
Δ = 4580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4580}=\sqrt{4*1145}=\sqrt{4}*\sqrt{1145}=2\sqrt{1145}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1145}}{2*-40}=\frac{70-2\sqrt{1145}}{-80} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1145}}{2*-40}=\frac{70+2\sqrt{1145}}{-80} $
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