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-5(-2x+8)x=5
We move all terms to the left:
-5(-2x+8)x-(5)=0
We multiply parentheses
10x^2-40x-5=0
a = 10; b = -40; c = -5;
Δ = b2-4ac
Δ = -402-4·10·(-5)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-30\sqrt{2}}{2*10}=\frac{40-30\sqrt{2}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+30\sqrt{2}}{2*10}=\frac{40+30\sqrt{2}}{20} $
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